What is your problem spot in your approach?

[Stormed1]

Mine is knee bend. After bowling 7 years in a cast where I could'nt get down and swing my leg behind i have been working on breaking my muscle memory

[Aslan]

I have to disagree with the statement, based on logic only. The FIRST shot has to enter between two pins at a specified angle in order to carry a strike.

When shooting ONE pin, you have a target that is approximately 26" wide - the width of two bowling balls plus the width of the pin. All you have to do is to get a small portion of the ball to hit on either side of the pin, thus creating a larger target than you have on a first shot.

BUT....easier said than done!

WRONG! On a "technicality"...

I said it was harder to hit "just one pin"....I did NOT say, "It's harder to knock one pin over than knock 10 pins over." In other words...if you're in the 10th...and need ONE pin....is it easier to get ONE pin with a full rack out there...or just the one pin?

I never said anything about "strikes". Remember...I'm old school...we don't roll strikes unless we get lucky. We try to spare every frame and avoid splits.

[bowl1820]

I said it was harder to hit "just one pin"

If your throwing a straight ball ( or basically straight.) A single pin spare should be a easy spare. Depending on where the pin is on the deck, you'll have the widest margin of error.

You have hole almost 22 inches wide hole to put the whole ball through (Ball max. size is 8.595 and pin Max. is 4.766). Now the closer that pin gets to the gutters that margin starts dropping.


Now if your trying to hook that ball into the single pin, you've made it a lot harder. You've now added a lot more variables to the equation.

In other words...if you're in the 10th...and need ONE pin....is it easier to get ONE pin with a full rack out there...or just the one pin?

Now only in this context, would the statement "harder to hit "just one pin"" would be true. Because throwing a ball at ten pins and only needing one of them to fall "is" a lot simpler than shooting at a single pin. (But not a given: See "Ballard Ball").

[Aslan]

Now only in this context, would the statement "harder to hit "just one pin"" would be true. Because throwing a ball at ten pins and only needing one of them to fall "is" a lot simpler than shooting at a single pin. (But not a given: See "Ballard Ball").

And THAT was my context. And if ANYONE...has ANY amount of money...that they would like to bet me....I am VERY good at hitting "some" pins with a roll at a full rack of 10....yet if there's just the 10 pin (which hates me and has the goal in it's pin life to mentally destroy me)....I'll take your money ALL DAY missing that sucker. And I'll do all this blindofolded so you KNOW I'm not intentionally missing it.

Straight ball or hook...physics and chemistry dictate that as long as the pins are free standing and not obscenely heavy....the pins occupy nearly the entire lane....you probably have a 70% if throwing an object/ball in their direction of knocking at least one over. Of matter of fact...you actually have a very small percentage chance of NOT knocking over more than one! If only one pin remains...even if it's the 5 pin, dead center....that percentage (based purely on the laws of chemistry and physics) drops to 31% (7 and 10 pins would be closer to 15.5% as you stated..because you can't hit them on the one side).

So the toughest shot in bowling...by the numbers with a fresh rack of pins (obviously splits are the toughest shots)...is to hit ONLY a 7 pin or a 10 pin when throwing at a full rack (roughly 11% tops).

Disclaimer: I WISH this was not true...because my spare game is KILLING me...so if it was easy to hit those last 1-4 pins...ughhh....PARADISE!

[bowl1820]

So the toughest shot in bowling...by the numbers with a fresh rack of pins (obviously splits are the toughest shots)...is to hit ONLY a 7 pin or a 10 pin when throwing at a full rack

Actually picking 2 pins off a full rack is tougher.

A 292 game is the rarest game score, only about 20 have been shot. Because it requires getting only two pins on the last shot.

The easiest score to shoot is a 77, because theres 172,542,309,343,731, 946 ways to make it!

[manke]

Mine is i pitch my arm out!!

[Aslan]

Actually picking 2 pins off a full rack is tougher.

A 292 game is the rarest game score, only about 20 have been shot. Because it requires getting only two pins on the last shot.

The easiest score to shoot is a 77, because theres 172,542,309,343,731, 946 ways to make it!

I'm semi-attracted to you that you know that.

[Mike White]

If your throwing a straight ball ( or basically straight.) A single pin spare should be a easy spare. Depending on where the pin is on the deck, you'll have the widest margin of error.

You have hole almost 22 inches wide hole to put the whole ball through (Ball max. size is 8.595 and pin Max. is 4.766). Now the closer that pin gets to the gutters that margin starts dropping.

I covered this with billf a while back, but it looks like you have either forgotten, or disbelieve.

Lets assume were are shooting at the 5 pin, and we use your figures of 8.595, and 4.766 (I think the pin is slightly thinner at the point where the ball makes contact)

If the ball makes contact with the pin, the center of the ball must be within 6.6805 inches of the center of the pin. Since it can be on either side, the room for error would be 13.361 inches.

For a 10 pin, the gutter is approximately 2 inches right of the center of the 10 pin, so you have 8.6805 plus the slight amount where the ball is falling off the lane as it makes contact with the 10, but has not yet touched the gutter.

[bowl1820]

I covered this with billf a while back, but it looks like you have either forgotten, or disbelieve.

Lets assume were are shooting at the 5 pin, and we use your figures of 8.595, and 4.766 (I think the pin is slightly thinner at the point where the ball makes contact)

If the ball makes contact with the pin, the center of the ball must be within 6.6805 inches of the center of the pin. Since it can be on either side, the room for error would be 13.361 inches.

For a 10 pin, the gutter is approximately 2 inches right of the center of the 10 pin, so you have 8.6805 plus the slight amount where the ball is falling off the lane as it makes contact with the 10, but has not yet touched the gutter.

No I haven't forgotten, or disbelieve.

I said you have to put "the whole ball through" that 22" window, not part of the ball. If the whole ball is inside that 22", the center of the ball will be 6.6805 inches of the center of the pin.

Were both saying the same thing just different ways.
Your just saying the center of the ball has to pass through a 13" window, I'm just saying the whole ball has to pass through a 22" window. Both are doing the same thing.


Photo 3:


Photo 4:

(and yes I know that say's 21.95" , I said "almost 22 inches" not exactly 22)
" in photos 3 & 4, we have placed poster boards with a gap in between which illustrates just how much room you do have…from outside to outside. If you can fit your ball in the gap, you will make the spare. Photo 3 shows two balls and a 6-pin to hopefully help you realize the actual size of your target area.(Photos 3 & 4 here) Photo 4 shows the same target without the balls"



and Here's the 10 pin margin

[Aslan]

Uh oh...mommy and daddy are fighting again....